1. Tardigrade
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  4. 1, 2-dibromoethane reacts with alcoholic KOH to yield a product X. The hybridization state of the carbons present in X respectively are:

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Q. 1, 2-dibromoethane reacts with alcoholic KOH to yield a product X. The hybridization state of the carbons present in X respectively are:

EAMCETEAMCET 2005

Solution:

Alkyl halides give elimination reaction with alcoholic KOH and yield an alkene or alkyne (From dihalides) e.g., $ \underset{1,-2\text{dibromo}\,\text{ethane}}{\mathop{Br-C{{H}_{2}}-C{{H}_{2}}-Br}}\,\xrightarrow[\Delta ]{alc.KOH}\underset{acetylene}{\mathop{\overset{sp}{\mathop{CH}}\,\equiv C\overset{sp}{\mathop{H}}\,}}\, $ Hence, product has both carbon sp- hybrid.