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Chemistry
1.0 molal aqueous solution of an electrolyte X3Y2 is 25% ionized. The boiling point of the solution is (Kb for H2O= 0.52 K kg/mol)
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Q. $1.0$ molal aqueous solution of an electrolyte $X_{3}Y_{2}$ is 25% ionized. The boiling point of the solution is $(K_{b}$ for $H_{2}O= 0.52\, K\, kg/mol)$
Solutions
A
$375.5\, K$
8%
B
$374.04 \,K$
75%
C
$377.12 \,K$
3%
D
$373.25\, K$
15%
Solution:
$\underset{1-\alpha}{{x_{3}y_{2}}} \rightleftharpoons \underset{n \alpha}{{3x^{2+}}}+\underset{m\alpha}{{2y^{3-}}}$ for complete ionization,
$i=1+(m+n-1) \alpha$
$i=1+(2+3-1)\times 0.25=1+1=2$
$\Delta\,T_{b}=i\times Kb \times m=2\times 0.52\times 1=1.04$
B.P. of solution $(T_{b})=\Delta\,T_{b}+T^{\circ}_{b}=1.04+373$
$=374.04\,K$