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  4. 1.0 g of Mg is burnt with 0.28 g of O2 in a closed vessel. Which reactant is left in excess and how much ?

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Q. $1.0 \, g$ of Mg is burnt with 0.28 g of $O_2$ in a closed vessel. Which reactant is left in excess and how much ?

KCETKCET 2018Some Basic Concepts of Chemistry

Solution:

$2Mg + O_2 \to 2MgO$

48 g of Mg requires 32 g of $O_2$ ?

requires 0.28 g of $O_2$

Mass of magnesium required = $\frac{48 \times 0.28}{32} = 0.42 \, g $
But 1 g of Mg is available. Thus, Mg is the excess reagent.
Excess of Mg left behind $= 1 - 0.42 = 0.58\, g$