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Q.
$1.0$ g of a monobasic acid when completely acted upon Mg gave $1.301$ g of anhydrous Mg salt. Equivalent weight of acid is
Some Basic Concepts of Chemistry
Solution:
$\frac{\text{Ew of acid}}{\text{Ew of salt of Mg}} =\frac{\text{Weight of acid}}{\text{Weight of salt}}$
$Mg + 2HCl$ (monobasic acid) $\to MgCl_{2} + H_{2}$
Let $Ew$ of acid $= Ew$ of $H + Ew$ of acid radical
$\therefore $ $Ew$ of salt of $Mg = Ew$ of $Mg + Ew$ of acid radical
$\therefore \frac{\text{Ew of acid}}{\text{Ew of Mg salt}} =\frac{\text{Weight of acid}}{\text{Weight of Mg salt}}$
$\Rightarrow \frac{\text{Ew of H + Ew of acid radical (E)}}{\text{Ew of Mg + Ew of acid radical (E)}} =\frac{1.0}{1.301}$
$\Rightarrow \frac{1+E}{12+E} =\frac{1.0}{1.301}$
$\therefore E= 35.54$
$\therefore $ $Ew$ of acid $= Ew$ of $H + Ew$ of acid radical
$= 1 + 35.54 = 36.54$