Question

$0.92 \,g$ of an organic compound was analysed by combustion method. The mass of the $U$-tube increased by $1.08 \,g$. What is the percentage of hydrogen in the compound?

• A. $13.04\%$
• B. $52.317\%$
• C. $65.21\%$
• D. $11.30\%$

Answer 1

Answer: (A)

Increase in mass of $U$-tube = $1.08\, g$
Mass of water formed = $1.08 \,g$
$18 \,g\, H_{2}O \equiv 2\, g\, H$
$1.08 \,g \,H_{2}O =\frac{2}{18} \times 1.08$
% of hydrogen $= \frac{2}{18} \times \frac{1.08}{0.92} \times 100=13.04\%$