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  4. 0.71 g of chlorine combines with certain weight of a metal giving 1.11 g of its chloride. The equivalent weight of the metal is

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Q. $ 0.71\,g $ of chlorine combines with certain weight of a metal giving $ 1.11\,g $ of its chloride. The equivalent weight of the metal is

Punjab PMETPunjab PMET 2001Some Basic Concepts of Chemistry

Solution:

Let metal chloride be $MCl _{n}$
$\therefore $ equivalents of metal
=equivalents of chlorine
or $\frac{1.11-0.71}{E} =\frac{0.71}{35.5}$
$\therefore E=20$