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Q. 0.6 g of a solute is dissolved in 0.1 litre of a solvent which develops an osmotic pressure of 1.23 atm at $27^{\circ}C$. The molecular mass of the substance is

Solutions

Solution:

$m=\frac{wRT}{PV}$
$=\frac{0.6\times0.082\times300}{1.23\times0.1}=120$