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Q. $0.52 g$ of a dibasic acid required $100 mL$ of $0.2 N NaOH$ for complete neutralization. The equivalent weight of acid is

Redox Reactions

Solution:

Meq. of Acid = Meq. of $NaOH$

$\frac{0.52}{ E } \times 1000=100 \,\,\,\,0.2$

$\therefore E =26$