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Q. $0.5$ mole of $H _{2}( g )$ and 1.0 mole of $HI ( g )$ (but no $I _{2}$ ) are added to a $1.0\, L$ vessel and allowd to reach equilibrium according to the following reaction: $H _{2}+ I _{2} \rightleftharpoons 2 HI ( g )$ If $x$ is the equilibrium concentration of $I_{2},$ the correct equilibrium constant expression is

Equilibrium

Solution:

$ \underset{0.5- x }{H _{2}}+\underset{1}{ I _{2}}= \underset{1 - 2x}{2 HI ( g )}$