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  4. 0.5 F of electricity is passed through 500 mL of copper sulphate solution. The amount of copper which can be deposited will be

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Q. $0.5 \,F$ of electricity is passed through $500 \, mL$ of copper sulphate solution. The amount of copper which can be deposited will be

NEETNEET 2022Electrochemistry

Solution:

$Cu ^{2+}+2 e ^{-} \longrightarrow Cu$
$2\, F =1\, mol$ of $Cu =63.5 \,g$ of $Cu$
$0.5\, F =\frac{63.5}{2} \times 0.5=15.8 \,g$