1. Tardigrade
  2. Question
  3. Chemistry
  4. 0.45 g of an acid of molecular weight 90 was neutralized by 20 mL of a 0.5 N caustic potash. The basicity of an acid is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. $0.45\, g$ of an acid of molecular weight $90$ was neutralized by $20 \,mL$ of a $0.5 \,N$ caustic potash. The basicity of an acid is

Some Basic Concepts of Chemistry

Solution:

Equivalents of $KOH$ used $=\frac{20 \times 0.5}{1000}=0.01$
Moles of acid $=\frac{0.45}{90}=0.005\, mol$
If basicity of acid $= x$
Then equivalents of acid $=0.005 x$
$\therefore 0.005 x =0.01$
$\therefore x=2$