Thank you for reporting, we will resolve it shortly
Q.
0.365 g of an organic compound containing nitrogen gave 56 ml of nitrogen at S.T.P. The percentage nitrogen in the given compound is
NTA AbhyasNTA Abhyas 2022
Solution:
It is Duma's method used to find % of nitrogen
$\%N=\frac{28 \times V \, a t \, S T P \times 100}{22400 \times W}=\frac{28 \times 56 \times 100}{22400 \times 0.236}=19.18\%$