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  4. 0.3 g of an oxalate salt was dissolved in 100 ml solution. The solution requires 90 mL of (N/2)KMnO4 for complete oxidation. The % of oxalate ion in salt is

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Q. 0.3 g of an oxalate salt was dissolved in 100 ml solution. The solution requires 90 mL of $ \frac{N}{2}KMn{{O}_{4}} $ for complete oxidation. The % of oxalate ion in salt is

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Solution:

Meq. of oxalate = Meq. of $ KMn{{O}_{4}} $ $ \frac{w}{88/2}\times 1000=90\frac{1}{20} $ $ \therefore $ w oxalate ion = 0.198 g $ \therefore $ of oxalate ion $ =\frac{0.198}{0.3}\times 100=66% $