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  4. 0.2 moles of HCl and 0.1 moles of calcium chloride were dissolved in water to have the molarity of Cl- ions is

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Q. 0.2 moles of HCl and 0.1 moles of calcium chloride were dissolved in water to have the molarity of $Cl^-$ ions is

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Solution:

0.2 moles of HCl gives $Cl^-$ ions = 0.2 moles 0.1 moles of $CaCl_2$ gives $Cl^-$ ions = 0.2 moles. Total moles of $Cl^-$ ions in 500 mL = 0.4 Molarity of $Cl^- $ ions = 0.8 M.