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Q. 0.2 F capacitor is charge to 600 V by a battery, on removing the battery, it is connected with another parallel plate condenser of I F . The potential decreases to

Bihar CECEBihar CECE 2010Electrostatic Potential and Capacitance

Solution:

By using charge conservation
$ \, \, \, \, \, 0.2 \times 600 = (0.2 + 1)V$
$ V = \frac {0.2 \times 600}{1.2} = 100V$