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  4. 0.126 g of acid required 20 mL of 0.1 N NaOH for complete neutralisation. The equivalent mass of an acid is

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Q. 0.126 g of acid required 20 mL of 0.1 N NaOH for complete neutralisation. The equivalent mass of an acid is

Some Basic Concepts of Chemistry

Solution:

Let equivalent mass be $E$
$\therefore $ g-equivalent of acid $=\frac{0.126}{E}$
$G$-equivalents of acid = $G$ equi. of base
or $\frac{0.126}{E}=20\times10^{-3}\times 0.1$
or $E=\frac{0.126\times10^{3}}{20\times0.1}$
$=63$