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Q. $0.06\%\, (w/v)$ aqueous solution of urea is isotonic with

KCETKCET 2015Solutions

Solution:

$0.06 \%\,( w / V )$ aqueous solution of urea $=\frac{0.06}{100}$

$=6 \times 10^{-4}\, g$

This means that $6 \times 10^{-4} \,g$ of urea is present in $1L$ of solution.

Molecular mass of urea image

Molarity of urea solution

$=\frac{w \times 1000}{M \times \text { volume }( mL )} $

$=\frac{0.06 \times 1000}{100 \times 60}=0.01 \,M$

$\therefore 0.01 M$ glucose solution is isotonic with $0.06 \%$ (w/V) solution of urea.