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Q. 0.01 mole of a non-electrolyte is dissolved in 10 g of water. The molality of the solution is

Jharkhand CECEJharkhand CECE 2009

Solution:

$ \text{Molarlity}\,(m)=\frac{\text{number}\,\text{of}\,\text{moles}\,\text{of}\,\text{solute}}{\text{weight}\,\text{of}\,\text{solcent}\,\text{in}\,\text{kg}} $
$ =\frac{0.01}{10\times {{10}^{-3}}} $
$ =\frac{0.01\times {{10}^{3}}}{10} $
$ =1\,m $