Thank you for reporting, we will resolve it shortly
Q.
$0.004 \,M\,Na_2SO_4$ is isotonic with $0.01 \,M$ glucose. Degree of dissociation of $Na_2SO_4$ is
IIT JEEIIT JEE 2004Solutions
Solution:
For isotonic solutions, they must have same concentrations of ions, Therefore,
$0.004 i\left( Na _{2} SO _{4}\right) =0.01 $
$\Rightarrow i =\frac{0.01}{0.004}=2.5$
$i =1+2 \alpha=2.5 $
$\alpha=0.75$
or $75 \%$ dissociation
