Young's double slit experiment is performed with sodium (Yellow) light of wavelength 589.3 nm and the interference pattern is observed on a screen 100 cm away. The 10 th bright fringe has its centre at a distance of 12 nm from the central maximum. The separation between the slits is

Question

Young's double slit experiment is performed with sodium (Yellow) light of wavelength 589.3 nm and the interference pattern is observed on a screen 100 cm away. The 10 th bright fringe has its centre at a distance of 12 nm from the central maximum. The separation between the slits is (A) 0.49 mm (B) 0.6 mm (C) 0.7 mm (D) 0.53 mm

Tardigrade Admin · Accepted Answer

Position of 10th bright fringe =(10 λ D/d) Also, (10 λ D/d)=12 ⇒ d=(10 λ D/12) The separation between the slits =(10 × 589.3 × 10-9 × 1/12 × 10-3) =4.9 × 10-4 m =0.49 mm

Q. Young's double slit experiment is performed with sodium (Yellow) light of wavelength $589.3 nm$ and the interference pattern is observed on a screen $100 c m$ away. The 10 th bright fringe has its centre at a distance of $12 nm$ from the central maximum. The separation between the slits is

0.49 mm

0.6 mm

0.7 mm

0.53 mm

Position of $10 t h$ bright fringe $= \frac{10 λ D}{d}$
Also, $\frac{10 λ D}{d} = 12$
$\Rightarrow d = \frac{10 λ D}{12}$
The separation between the slits
$= \frac{10 \times 589.3 \times 1 0 ^{- 9} \times 1}{12 \times 1 0 ^{- 3}}$
$= 4.9 \times 1 0^{- 4} m = 0.49 mm$

Q. Young's double slit experiment is performed with sodium (Yellow) light of wavelength 589.3nm and the interference pattern is observed on a screen 100cm away. The 10 th bright fringe has its centre at a distance of 12nm from the central maximum. The separation between the slits is