Xenon crystallises in face-centered cubic lattice, and the edge of the unit cell is 620 pm. The radius of a xenon atom is

Question

Xenon crystallises in face-centered cubic lattice, and the edge of the unit cell is 620 pm. The radius of a xenon atom is (A) 438.5 pm (B) 219.20 pm (C) 536.94 pm (D) 265.5 pm

Tardigrade Admin · Accepted Answer

For an fcc lattice, 4r = √2a, where a = 620 pm Or r = (√2/4) . a = (1/2√2). a = (1/2√2) . 620 = 219.20 pm

Q. Xenon crystallises in face-centered cubic lattice, and the edge of the unit cell is $620 p m$ . The radius of a xenon atom is

$438.5$ pm

$219.20$ pm

$536.94$ pm

$265.5$ pm

For an fcc lattice, $4 r = 2 a$ , where $a = 620 p m$
Or $r = \frac{2}{4} . a = \frac{1}{2 2}$ .
$a = \frac{1}{2 2} .620 = 219.20 p m$

Q. Xenon crystallises in face-centered cubic lattice, and the edge of the unit cell is 620pm. The radius of a xenon atom is

438.5 pm

219.20 pm

536.94 pm

265.5 pm