X(g) longrightarrow X+(g)+e-, Δ H=+720 kJ mol -1 Calculate the amount of energy required to convert 110 mg of ' X ' atom in gaseous state into X+ion. (Atomic wt. for X=7 g / mol )

Question

X(g) longrightarrow X+(g)+e-, Δ H=+720 kJ mol -1 Calculate the amount of energy required to convert 110 mg of ' X ' atom in gaseous state into X+ion. (Atomic wt. for X=7 g / mol ) (A) 10.4 kJ (B) 12.3 kJ (C) 11.3 kJ (D) 14.5 kJ

Tardigrade Admin · Accepted Answer

Energy required for 1 mol=720 × 103 J According to question- Energy required for 110 mg =720 × 103 ×((110 × 10-3/7)) =11314.2 J=11.3 kJ

Q. $X_{(g)} ⟶ X^{+} (g) + e^{-}$ ,
$Δ H = + 720 k J m o l^{- 1}$
Calculate the amount of energy required to convert $110 m g$ of ' $X$ ' atom in gaseous state into $X^{+}$ ion. (Atomic wt. for $X = 7 g / m o l$ )

10.4 kJ

12.3 kJ

11.3 kJ

14.5 kJ

Energy required for $1 m o l = 720 \times 1 0^{3} J$
According to question-
Energy required for $110 m g = 720 \times 1 0^{3} \times (\frac{110 \times 1 0 ^{- 3}}{7})$
$= 11314.2 J = 11.3 k J$

Q. X(g)​⟶X+(g)+e−, ΔH=+720kJmol−1 Calculate the amount of energy required to convert 110mg of ' X ' atom in gaseous state into X+ion. (Atomic wt. for X=7g/mol )