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Question
Physics
Work done in splitting a drop of water of 1 mm radius into 10 droplets is (surface tension of water =72 × 10-3J/m2 )
Q. Work done in splitting a drop of water of 1 mm radius into 10 droplets is (surface tension of water
=
72
×
10
−
3
J
/
m
2
)
4020
196
Rajasthan PMT
Rajasthan PMT 2010
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A
9.58
×
10
−
5
J
B
8.95
×
10
−
5
J
C
5.89
×
10
−
5
J
D
5.98
×
10
−
6
J
Solution:
Work done in splitting a water drop of radius
R
into
n
drops of equal size
=
4
π
R
2
T
(
n
1/3
−
1
)
=
4
π
×
(
10
−
3
)
2
×
72
×
10
−
3
×
(
10
6/3
−
1
)
=
4
π
×
10
−
6
×
72
×
10
−
3
×
99
=
8.95
×
10
−
5
J