Question

Which term of the series $3+8+13+18+....$ is 498:

• A. 95th
• B. 100th
• C. 102th
• D. 101th

Answer 1

Answer: (B)

If the difference of the consecutive terms is constant, then the series is in AP.
Given series is $3+8+13+18+....+498$
Here, $a=3,d=5,l=498$
As we know
$t_n=l=a+(n-1)d$
$\Rightarrow$ $498=3+(n-1)5$
$\Rightarrow$ $(n-1)=\frac{495}{5}$
$\Rightarrow$ $n-1=99$
$\Rightarrow n=100$