Which statement is incorrect?

Question

Which statement is incorrect? (A) Ni(CO)4-tetrahedral, paramagnetic (B) [Ni(CN)4]2--square planar, diamagnetic (C) Ni(CO)4-tetrahedral, diamagnetic (D) [Ni(Cl)4]2- tetrahedral, paramagnetic

Tardigrade Admin · Accepted Answer

In Ni ( CO )4 complex, Ni ( CO )4 will have 3 d 10 configuration. Hence [ Ni ( CO )4] will have tetrahedral geometry but diamagnetic as there are no unpaired electrons.

Q. Which statement is incorrect?

$N i (CO)_{4}$ -tetrahedral, paramagnetic

$[N i (CN)_{4}]^{2 -}$ -square planar, diamagnetic

$N i (CO)_{4}$ -tetrahedral, diamagnetic

$[N i (Cl)_{4}]^{2 -}$ tetrahedral, paramagnetic

In $N i (CO)_{4}$ complex, $N i (CO)_{4}$ will have $3 d^{10}$ configuration.
Hence $[N i (CO)_{4}]$ will have tetrahedral geometry but diamagnetic as there are no unpaired electrons.

Q. Which statement is incorrect?

Ni(CO)4​-tetrahedral, paramagnetic

[Ni(CN)4​]2−-square planar, diamagnetic

Ni(CO)4​-tetrahedral, diamagnetic

[Ni(Cl)4​]2− tetrahedral, paramagnetic

In Ni(CO)4​ complex, Ni(CO)4​ will have 3d10 configuration. Hence [Ni(CO)4​] will have tetrahedral geometry but diamagnetic as there are no unpaired electrons.

$N i (CO)_{4}$ -tetrahedral, paramagnetic

$[N i (CN)_{4}]^{2 -}$ -square planar, diamagnetic

$N i (CO)_{4}$ -tetrahedral, diamagnetic

$[N i (Cl)_{4}]^{2 -}$ tetrahedral, paramagnetic

In $N i (CO)_{4}$ complex, $N i (CO)_{4}$ will have $3 d^{10}$ configuration.
Hence $[N i (CO)_{4}]$ will have tetrahedral geometry but diamagnetic as there are no unpaired electrons.