Which reaction result in the formation of a pair of enantiomers?

Question

Which reaction result in the formation of a pair of enantiomers? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Reaction (a) (c) goes via SN 2 mechanism. Reaction (b) (d) proceeds via S N l mechanism. S N 1 involves formation of a planar carbocation hence formation of a pair of enantiomer results, provided the carbon bearing the leaving group becomes chiral after the nucleophillic attack:

Q. Which reaction result in the formation of a pair of enantiomers?

Reaction (a) & (c) goes via $S_{N} 2$ mechanism. Reaction (b) & (d) proceeds via $S_{N}$ l mechanism. $S_{N} 1$ involves formation of a planar carbocation $&$ hence formation of a pair of enantiomer results, provided the carbon bearing the leaving group becomes chiral after the nucleophillic attack:

Q. Which reaction result in the formation of a pair of enantiomers?

Reaction (a) & (c) goes via SN​2 mechanism. Reaction (b) & (d) proceeds via SN​ l mechanism. SN​1 involves formation of a planar carbocation & hence formation of a pair of enantiomer results, provided the carbon bearing the leaving group becomes chiral after the nucleophillic attack: