Which one of the following statements regarding Henry's law is not correct?

Question

Which one of the following statements regarding Henry's law is not correct? (A) The value of KH increases with function of the nature of the gas. (B) Higher the value of KH at a given pressure, higher is the solubility of the gas in the liquids (C) The partial pressure of the gas in vapour phase is proportional to the mole fraction of of the gas in the solution. (D) Different gases have different KH (Henry's law constant) value at the same temperature.

Tardigrade Admin · Accepted Answer

Liquid solution Pg a s=KH× Xg a sasKH propto (1/Xg a s) So, more is KH less is solubility. Solubility of gases is less at higher temperature. So more is the temperature more is the KH as KH propto (1/s o l u b i l i t y) propto temperature.

Q. Which one of the following statements regarding Henry's law is not correct?

The value of $K_{H}$ increases with function of the nature of the gas.

Higher the value of $K_{H}$ at a given pressure, higher is the solubility of the gas in the liquids

The partial pressure of the gas in vapour phase is proportional to the mole fraction of of the gas in the solution.

Different gases have different $K_{H}$ (Henry's law constant) value at the same temperature.

Liquid solution
$P_{g a s} = K_{H} \times X_{g a s} a s K_{H} \propto \frac{1}{X _{g a s}}$
So, more is $K_{H}$ less is solubility.
Solubility of gases is less at higher temperature.
So more is the temperature more is the $K_{H}$ as $K_{H} \propto \frac{1}{so l u bi l i t y} \propto$ temperature.

Q. Which one of the following statements regarding Henry's law is not correct?

The value of KH​ increases with function of the nature of the gas.

Higher the value of KH​ at a given pressure, higher is the solubility of the gas in the liquids

The partial pressure of the gas in vapour phase is proportional to the mole fraction of of the gas in the solution.

Different gases have different KH​ (Henry's law constant) value at the same temperature.

Liquid solution Pgas​=KH​×Xgas​asKH​∝Xgas​1​ So, more is KH​ less is solubility. Solubility of gases is less at higher temperature. So more is the temperature more is the KH​ as KH​∝solubility1​∝ temperature.

The value of $K_{H}$ increases with function of the nature of the gas.

Higher the value of $K_{H}$ at a given pressure, higher is the solubility of the gas in the liquids

Different gases have different $K_{H}$ (Henry's law constant) value at the same temperature.

Liquid solution
$P_{g a s} = K_{H} \times X_{g a s} a s K_{H} \propto \frac{1}{X _{g a s}}$
So, more is $K_{H}$ less is solubility.
Solubility of gases is less at higher temperature.
So more is the temperature more is the $K_{H}$ as $K_{H} \propto \frac{1}{so l u bi l i t y} \propto$ temperature.