Which of the following would not give 2 -phenylbutane as the major product in a Friedel-Crafts alkylation reaction with benzene?

Question

Which of the following would not give 2 -phenylbutane as the major product in a Friedel-Crafts alkylation reaction with benzene? (A) 1 -butene + HF (B) 2 -butanol + H2SO4 (C) Butanoylchloride + AlCl3 then textZn-Hg/HCl (D) Butyl chloride + AlCl3

Tardigrade Admin · Accepted Answer

The Friedel - crafts alkylation reaction will give propyl phenyl ketone which on further
Clemmensen's reduction will give butyl benzene.

C_{6} H_{6} + C H_{3} C H_{2} C H_{2} COCl A lC l_{3} C_{6} H_{5} COC H_{2} C H_{2} C H_{3} Z n - H g / H Cl Butylbenzene C_{6} H_{5} C H_{2} C H_{2} C H_{2} C H_{3}

Rest other will give 2-phenylbutane as in them rearrangement of carbocation is possible.

Q. Which of the following would not give $2$ -phenylbutane as the major product in a Friedel-Crafts alkylation reaction with benzene?

$1$ -butene + $H F$

$2$ -butanol + $H_{2} S O_{4}$

Butanoylchloride + $A lC l_{3}$ then $Zn-Hg/HCl$

Butyl chloride + $A lC l_{3}$

Q. Which of the following would not give 2 -phenylbutane as the major product in a Friedel-Crafts alkylation reaction with benzene?

1 -butene + HF

2 -butanol + H2​SO4​

Butanoylchloride + AlCl3​ then Zn-Hg/HCl

Butyl chloride + AlCl3​

Q. Which of the following would not give $2$ -phenylbutane as the major product in a Friedel-Crafts alkylation reaction with benzene?

$1$ -butene + $H F$

$2$ -butanol + $H_{2} S O_{4}$

Butanoylchloride + $A lC l_{3}$ then $Zn-Hg/HCl$

Butyl chloride + $A lC l_{3}$