Which of the following will produce a buffer solution when mixed in equal volumes?

Question

Which of the following will produce a buffer solution when mixed in equal volumes? (A) 0.1 mol dm-3 NH4OH and 0.1 mol dm-3 HCl (B) 0.05 mol dm-3 NH4OH and 0.1 mol dm-3 HCl (C) 0.1 mol dm-3 NH4OH and 0.05 mol dm-3 HCl (D) 0.1 mol dm-3 CH3COONa and 0.1 mol dm-3 NaOH

Tardigrade Admin · Accepted Answer

In 0.1 mol dm-3 NH4OH and 0.05 mol dm-3 HCl, total amount of HCl reacts with NH4OH to form NH4Cl and some NH4OH will be left unreacted. Thus, the resultant solution contains NH4Cl and NH4OH which will produce a buffer solution.

Q. Which of the following will produce a buffer solution when mixed in equal volumes?

$0.1 m o l d m^{- 3} N H_{4} O H$ and $0.1 m o l d m^{- 3} H Cl$

$0.05 m o l d m^{- 3} N H_{4} O H$ and $0.1 m o l d m^{- 3} H Cl$

$0.1 m o l d m^{- 3} N H_{4} O H$ and $0.05 m o l d m^{- 3} H Cl$

$0.1 m o l d m^{- 3} C H_{3} COON a$ and $0.1 m o l d m^{- 3} N a O H$

In $0.1 m o l d m^{- 3} N H_{4} O H$ and $0.05 m o l d m^{- 3} H Cl$ , total amount of $H Cl$ reacts with $N H_{4} O H$ to form $N H_{4} Cl$ and some $N H_{4} O H$ will be left unreacted. Thus, the resultant solution contains $N H_{4} Cl$ and $N H_{4} O H$ which will produce a buffer solution.

Q. Which of the following will produce a buffer solution when mixed in equal volumes?

0.1moldm−3NH4​OH and 0.1moldm−3HCl

0.05moldm−3NH4​OH and 0.1moldm−3HCl

0.1moldm−3NH4​OH and 0.05moldm−3HCl

0.1moldm−3CH3​COONa and 0.1moldm−3NaOH

In 0.1moldm−3NH4​OH and 0.05moldm−3HCl, total amount of HCl reacts with NH4​OH to form NH4​Cl and some NH4​OH will be left unreacted. Thus, the resultant solution contains NH4​Cl and NH4​OH which will produce a buffer solution.

$0.1 m o l d m^{- 3} N H_{4} O H$ and $0.1 m o l d m^{- 3} H Cl$

$0.05 m o l d m^{- 3} N H_{4} O H$ and $0.1 m o l d m^{- 3} H Cl$

$0.1 m o l d m^{- 3} N H_{4} O H$ and $0.05 m o l d m^{- 3} H Cl$

$0.1 m o l d m^{- 3} C H_{3} COON a$ and $0.1 m o l d m^{- 3} N a O H$

In $0.1 m o l d m^{- 3} N H_{4} O H$ and $0.05 m o l d m^{- 3} H Cl$ , total amount of $H Cl$ reacts with $N H_{4} O H$ to form $N H_{4} Cl$ and some $N H_{4} O H$ will be left unreacted. Thus, the resultant solution contains $N H_{4} Cl$ and $N H_{4} O H$ which will produce a buffer solution.