Which of the following transition element, shows the highest oxidation state?

Question

Which of the following transition element, shows the highest oxidation state? (A) Cr (B) V (C) Fe (D) Mn

Tardigrade Admin · Accepted Answer

Manganese has the following electronic configuration 25Mn=1s2,2s22p6,3s23p63d5,4s2 It shows +7 oxidation state by losing all the seven electrons in 3d and 4s-sub-shells. Thus, it shows maximum oxidation state. (e.g., in KMnO4, O.S. of Mn=+7 )

Q. Which of the following transition element, shows the highest oxidation state?

Cr

V

Fe

Mn

Manganese has the following electronic configuration $_{25} M n = 1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{5}, 4 s^{2}$ It shows +7 oxidation state by losing all the seven electrons in 3d and 4s-sub-shells. Thus, it shows maximum oxidation state. (e.g., in $K M n O_{4},$ O.S. of $M n = + 7$ )

Q. Which of the following transition element, shows the highest oxidation state?

Cr

V

Fe

Mn

Manganese has the following electronic configuration 25​Mn=1s2,2s22p6,3s23p63d5,4s2 It shows +7 oxidation state by losing all the seven electrons in 3d and 4s-sub-shells. Thus, it shows maximum oxidation state. (e.g., in KMnO4​, O.S. of Mn=+7 )

Manganese has the following electronic configuration $_{25} M n = 1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{5}, 4 s^{2}$ It shows +7 oxidation state by losing all the seven electrons in 3d and 4s-sub-shells. Thus, it shows maximum oxidation state. (e.g., in $K M n O_{4},$ O.S. of $M n = + 7$ )