Which of the following sets of quantum numbers is not allowed?

Question

Which of the following sets of quantum numbers is not allowed? (A) n =3,1=2, m l =0, s =+(1/2) (B) n =3,1=2, m 1=-2, s =+(1/2) (C) n =3,1=3, m l =-3, s =-(1/2) (D) n =3,1=0, m 1=0, s =-(1/2)

Tardigrade Admin · Accepted Answer

1=0,1,2 ldots ldots(n-1) ∴ text for n =3 1=0,1,2 ⇒ 1=3 not possible for n =3

Q. Which of the following sets of quantum numbers is not allowed?

$n = 3, 1 = 2, m_{l} = 0, s = + \frac{1}{2}$

$n = 3, 1 = 2, m_{1} = - 2, s = + \frac{1}{2}$

$n = 3, 1 = 3, m_{l} = - 3, s = - \frac{1}{2}$

$n = 3, 1 = 0, m_{1} = 0, s = - \frac{1}{2}$

$1 = 0, 1, 2 \dots\dots (n - 1)$
$∴ for n = 3$
$1 = 0, 1, 2$
$\Rightarrow 1 = 3$
not possible for $n = 3$

Q. Which of the following sets of quantum numbers is not allowed?

n=3,1=2,ml​=0,s=+21​

n=3,1=2,m1​=−2,s=+21​

n=3,1=3,ml​=−3,s=−21​

n=3,1=0,m1​=0,s=−21​

1=0,1,2……(n−1) ∴ for n=3 1=0,1,2 ⇒1=3 not possible for n=3

$n = 3, 1 = 2, m_{l} = 0, s = + \frac{1}{2}$

$n = 3, 1 = 2, m_{1} = - 2, s = + \frac{1}{2}$

$n = 3, 1 = 3, m_{l} = - 3, s = - \frac{1}{2}$

$n = 3, 1 = 0, m_{1} = 0, s = - \frac{1}{2}$

$1 = 0, 1, 2 \dots\dots (n - 1)$
$∴ for n = 3$
$1 = 0, 1, 2$
$\Rightarrow 1 = 3$
not possible for $n = 3$