Which of the following represents a standing wave?

Question

Which of the following represents a standing wave? (A) y=A sin (ω t-k x) (B) y=A e-b x sin (ω t-k x+α) (C) y=A sin k x sin (ω t-θ) (D) y=(a x+b) sin (ω t-k x)

Tardigrade Admin · Accepted Answer

In a standing wave, the amplitude is an oscillating function of

x

in :

y = A sin k x sin (ω t + θ)

A sin k x

represents the amplitude and is of the correct form to be a standing wave.

y = 3 sin \frac{π x}{3} cos 40 π t

Q. Which of the following represents a standing wave?

$y = A sin (ω t - k x)$

$y = A e^{- b x} sin (ω t - k x + α)$

$y = A sin k x sin (ω t - θ)$

$y = (a x + b) sin (ω t - k x)$

In a standing wave, the amplitude is an oscillating function of $x$ in :
$y = A sin k x sin (ω t + θ)$
$A sin k x$ represents the amplitude and is of the correct form to be a standing wave.
$y = 3 sin \frac{π x}{3} cos 40 π t$

Q. Which of the following represents a standing wave?

y=Asin(ωt−kx)

y=Ae−bxsin(ωt−kx+α)

y=Asinkxsin(ωt−θ)

y=(ax+b)sin(ωt−kx)

In a standing wave, the amplitude is an oscillating function of x in : y=Asinkxsin(ωt+θ) Asinkx represents the amplitude and is of the correct form to be a standing wave. y=3sin3πx​cos40πt

$y = A sin (ω t - k x)$

$y = A e^{- b x} sin (ω t - k x + α)$

$y = A sin k x sin (ω t - θ)$

$y = (a x + b) sin (ω t - k x)$

In a standing wave, the amplitude is an oscillating function of $x$ in :
$y = A sin k x sin (ω t + θ)$
$A sin k x$ represents the amplitude and is of the correct form to be a standing wave.
$y = 3 sin \frac{π x}{3} cos 40 π t$