Which of the following pairs shows a negative deviation from Raoult’s law?

Question

Which of the following pairs shows a negative deviation from Raoult’s law? (A) Acetone-benzene (B) Acetone-ether (C) Acetone-chloroform (D) Benzene-methanol

Tardigrade Admin · Accepted Answer

When acetone and chloroform are mixed, the hydrogen-bonding takes place between the two due to which escaping tendency of either of the liquid solution becomes less. underset textHydrogen bonding between chloroform and acetoneCl- underset overset|Cl overset underset|ClCl-H - - - - - - - - O = C<CH3CH3

Q. Which of the following pairs shows a negative deviation from Raoult’s law?

Acetone-benzene

Acetone-ether

Acetone-chloroform

Benzene-methanol

When acetone and chloroform are mixed, the hydrogen-bonding takes place between the two due to which escaping tendency of either of the liquid solution becomes less. $Hydrogen bonding between chloroform and acetone Cl - C ∣ l Cl ∣ C l - H - - - - - - - - O = C <_{C H_{3}}^{C H_{3}}$

Q. Which of the following pairs shows a negative deviation from Raoult’s law?

Acetone-benzene

Acetone-ether

Acetone-chloroform

Benzene-methanol

When acetone and chloroform are mixed, the hydrogen-bonding takes place between the two due to which escaping tendency of either of the liquid solution becomes less. Hydrogen bonding between chloroform and acetoneCl−C∣lCl∣C​l​−H−−−−−−−−O=C<CH3​CH3​​​

When acetone and chloroform are mixed, the hydrogen-bonding takes place between the two due to which escaping tendency of either of the liquid solution becomes less. $Hydrogen bonding between chloroform and acetone Cl - C ∣ l Cl ∣ C l - H - - - - - - - - O = C <_{C H_{3}}^{C H_{3}}$