Which of the following order of energies of molecular orbitals of N2 is correct?

Question

Which of the following order of energies of molecular orbitals of N2 is correct? (A) (π2py)< (σ2pz)<(π* 2px)≈(π* 2py) (B) (π2py) > (σ2pz) > (π* 2px)≈(π* 2py) (C) (π2py) < (σ2pz) > (π* 2px)≈(π* 2py) (D) (π2py) > (σ2pz) <(π* 2px)≈(π* 2py)

Tardigrade Admin · Accepted Answer

For molecules such as B2, C2, N2 etc. the increasing order of energies of various molecular orbitals is σ 1s < σ* 1s < σ 2s < σ* 2s <(π 2px=π 2py) < σ 2pz < (π* 2px = π* 2py) < σ* 2pz

Q. Which of the following order of energies of molecular orbitals of $N_{2}$ is correct?

$(π 2 p_{y}) < (σ 2 p_{z}) < (π^{} 2 p_{x}) \approx (π^{} 2 p_{y})$

$(π 2 p_{y}) > (σ 2 p_{z}) > (π^{} 2 p_{x}) \approx (π^{} 2 p_{y})$

$(π 2 p_{y}) < (σ 2 p_{z}) > (π^{} 2 p_{x}) \approx (π^{} 2 p_{y})$

$(π 2 p_{y}) > (σ 2 p_{z}) < (π^{} 2 p_{x}) \approx (π^{} 2 p_{y})$

For molecules such as $B_{2}, C_{2}, N_{2}$ etc. the increasing order of energies of various molecular orbitals is
$σ 1 s < σ^{} 1 s < σ 2 s < σ^{} 2 s < (π 2 p_{x} = π 2 p_{y}) < σ 2 p_{z} <$
$(π^{} 2 p_{x} = π^{} 2 p_{y}) < σ^{*} 2 p_{z}$

Q. Which of the following order of energies of molecular orbitals of N2​ is correct?

(π2py​)<(σ2pz​)<(π∗2px​)≈(π∗2py​)

(π2py​)>(σ2pz​)>(π∗2px​)≈(π∗2py​)

(π2py​)<(σ2pz​)>(π∗2px​)≈(π∗2py​)

(π2py​)>(σ2pz​)<(π∗2px​)≈(π∗2py​)