We know that nC02+nC12+⋯+nCn2=2nCn
and nC02−nC12+⋯+nCn2==<br/><br/>⎩⎨⎧<br/><br/>0,<br/><br/>nCn/2(−1)n/2if n is oddif n is even<br/><br/>
From these ,31C02−31C12+31C22−⋯−31C312=0 32C02−32C12+32C22−⋯+32C322=32C16 34C02−34C12+34C22−⋯+34C322=−34C17 32C02+32C12+32C22−⋯+32C322=64C32
Obviously 64C32, is greatest.