Which of the following is the correct order of acidic strength?

Question

Which of the following is the correct order of acidic strength? (A) Cl 3 CCOOH > Cl 2 CHCOOH > Cl.CH 2 COOH > CH 3 COOH (B) CH 3 COOH > ClCH 2 COOH > Cl 2 . CHCOOH > Cl 3 C . COOH (C) CH 3 COOH > Cl 3 C.COOH > Cl 2 . CHCOOH > Cl. CH 2 COOH (D) CH 3 COOH > Cl.CH 2 COOH > Cl 2 . CH COOH > Cl3.C. COOH

Tardigrade Admin · Accepted Answer

-Cl increases the polarity of - overset underset||OC - group because -Cl is electron withdrawing in nature. Therefore; the acidic strength of the compounds are: Cl 3 C . COOH > Cl 2 CHCOOH > ClCH 2 COOH > CH 3 COOH

Q. Which of the following is the correct order of acidic strength?

$C l_{3} CCOO H > C l_{2} C H COO H > Cl . C H_{2} COO H > C H_{3} COO H$

$C H_{3} COO H > ClC H_{2} COO H > C l_{2} . C H COO H > C l_{3} C . COO H$

$C H_{3} COO H > C l_{3} C . COO H > C l_{2} . C H COO H > Cl . C H_{2} COO H$

$C H_{3} COO H > Cl . C H_{2} COO H > C l_{2} . C H COO H > C l_{3} . C . COO H$

$- Cl$ increases the polarity of $- C ∣∣ O -$ group because $- Cl$ is electron withdrawing in nature.

Therefore; the acidic strength of the compounds are: $C l_{3} C . COO H > C l_{2} C H COO H > ClC H_{2} COO H > C H_{3} COO H$

Q. Which of the following is the correct order of acidic strength?

Cl3​CCOOH>Cl2​CHCOOH>Cl.CH2​COOH>CH3​COOH

CH3​COOH>ClCH2​COOH>Cl2​.CHCOOH>Cl3​C.COOH

CH3​COOH>Cl3​C.COOH>Cl2​.CHCOOH>Cl.CH2​COOH

CH3​COOH>Cl.CH2​COOH>Cl2​.CHCOOH>Cl3​.C.COOH

−Cl increases the polarity of −C∣∣O​− group because −Cl is electron withdrawing in nature. Therefore; the acidic strength of the compounds are: Cl3​C.COOH>Cl2​CHCOOH>ClCH2​COOH>CH3​COOH

$C l_{3} CCOO H > C l_{2} C H COO H > Cl . C H_{2} COO H > C H_{3} COO H$

$C H_{3} COO H > ClC H_{2} COO H > C l_{2} . C H COO H > C l_{3} C . COO H$

$C H_{3} COO H > C l_{3} C . COO H > C l_{2} . C H COO H > Cl . C H_{2} COO H$

$C H_{3} COO H > Cl . C H_{2} COO H > C l_{2} . C H COO H > C l_{3} . C . COO H$

$- Cl$ increases the polarity of $- C ∣∣ O -$ group because $- Cl$ is electron withdrawing in nature.

Therefore; the acidic strength of the compounds are: $C l_{3} C . COO H > C l_{2} C H COO H > ClC H_{2} COO H > C H_{3} COO H$