Which of the following is incorrect order?

Question

Which of the following is incorrect order? (A) CH3->CH3O->HO->H2O (Nucleophilicity in protic solvent) (B) Cl->CH3COO->CH3O->NH2- (Leaving group ability) (C) <img class="img-fluid question-image" alt="Option 3" src="https://cdn.tardigrade.in/q/nta/c-jiqqxsmz1vkdtmtm.jpg" /> Stability of alkane (D) CH3-CH2-F>CH3-CH2-Cl>CH3-CH2-Br>CH3-CH2-I(.Boilingpoint.)

Tardigrade Admin · Accepted Answer

(i) nucleophilicity propto negative charge density of at atom Solution

(order of nuclophilicity) neutral atom (ii) Cl->CH3COO->CH3O->NH2- leaving group ability propto (1/B a s i c s t r e n g t h) (iii) Stability of alkene propto number of hyper conjugative structures Solution

Q. Which of the following is incorrect order?

$C H_{3}^{-} > C H_{3} O^{-} > H O^{-} > H_{2} O$ (Nucleophilicity in protic solvent)

$C l^{-} > C H_{3} CO O^{-} > C H_{3} O^{-} > N H_{2}^{-}$ (Leaving group ability)

Stability of alkane

$C H_{3} - C H_{2} - F > C H_{3} - C H_{2} - Cl > C H_{3} - C H_{2} - B r > C H_{3} - C H_{2} - I (B o i l in g p o in t)$

Q. Which of the following is incorrect order?

CH3−​>CH3​O−>HO−>H2​O (Nucleophilicity in protic solvent)

Cl−>CH3​COO−>CH3​O−>NH2−​ (Leaving group ability)

Stability of alkane

CH3​−CH2​−F>CH3​−CH2​−Cl>CH3​−CH2​−Br>CH3​−CH2​−I(Boilingpoint)

(i) nucleophilicity ∝ negative charge density of at atom (order of nuclophilicity) neutral atom (ii) Cl−>CH3​COO−>CH3​O−>NH2−​ leaving group ability ∝Basicstrength1​ (iii) Stability of alkene ∝ number of hyper conjugative structures

$C H_{3}^{-} > C H_{3} O^{-} > H O^{-} > H_{2} O$ (Nucleophilicity in protic solvent)

$C l^{-} > C H_{3} CO O^{-} > C H_{3} O^{-} > N H_{2}^{-}$ (Leaving group ability)

$C H_{3} - C H_{2} - F > C H_{3} - C H_{2} - Cl > C H_{3} - C H_{2} - B r > C H_{3} - C H_{2} - I (B o i l in g p o in t)$