Which of the following is correct in terms of increasing work done for the same initial and final state?

Question

Which of the following is correct in terms of increasing work done for the same initial and final state? (A) Adiabatic < Isothermal < Isobaric (B) Isobaric < Adiabatic < Isothermal (C) Adiabatic < Isobaric < Isothermal (D) None of these

Tardigrade Admin · Accepted Answer

In thermodynamic process, work done is equal to the area covered by the P V curve with volume axis. Hence, according to graph shown W text adiabatic < W text isothermal < W text isobaric <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/6f63dae33fd8f3a8dd34f17b95159602-.png" />

Q. Which of the following is correct in terms of increasing work done for the same initial and final state?

Adiabatic < Isothermal < Isobaric

Isobaric < Adiabatic < Isothermal

Adiabatic < Isobaric < Isothermal

None of these

In thermodynamic process, work done is equal to the area covered by the $P V$ curve with volume axis.
Hence, according to graph shown
$W_{adiabatic} < W_{isothermal} < W_{isobaric}$

Q. Which of the following is correct in terms of increasing work done for the same initial and final state?

Adiabatic < Isothermal < Isobaric

Isobaric < Adiabatic < Isothermal

Adiabatic < Isobaric < Isothermal

None of these

In thermodynamic process, work done is equal to the area covered by the PV curve with volume axis. Hence, according to graph shown Wadiabatic ​<Wisothermal ​<Wisobaric​

In thermodynamic process, work done is equal to the area covered by the $P V$ curve with volume axis.
Hence, according to graph shown
$W_{adiabatic} < W_{isothermal} < W_{isobaric}$