Which of the following is arranged in the order of increasing radius of ions in aqueous solution?

Question

Which of the following is arranged in the order of increasing radius of ions in aqueous solution? (A) Li +< Na +< K +< Rb +< Cs + (B) Cs +< Rb +< K +< Na +< Li + (C) Rb +< Na +< Li +< Cs +< K + (D) Cs +< K +< Rb +< Li +< Na +

Tardigrade Admin · Accepted Answer

Li +has highest hydration enthalpy. Hence it is most hydrated ∴ Correct order of hydrated radii is Cs +< Rb +< K +< Na +< Li +

Q. Which of the following is arranged in the order of increasing radius of ions in aqueous solution?

$L i^{+} < N a^{+} < K^{+} < R b^{+} < C s^{+}$

$C s^{+} < R b^{+} < K^{+} < N a^{+} < L i^{+}$

$R b^{+} < N a^{+} < L i^{+} < C s^{+} < K^{+}$

$C s^{+} < K^{+} < R b^{+} < L i^{+} < N a^{+}$

$L i^{+}$ has highest hydration enthalpy.
Hence it is most hydrated
$∴$ Correct order of hydrated radii is
$C s^{+} < R b^{+} < K^{+} < N a^{+} < L i^{+}$

Q. Which of the following is arranged in the order of increasing radius of ions in aqueous solution?

Li+<Na+<K+<Rb+<Cs+

Cs+<Rb+<K+<Na+<Li+

Rb+<Na+<Li+<Cs+<K+

Cs+<K+<Rb+<Li+<Na+

Li+has highest hydration enthalpy. Hence it is most hydrated ∴ Correct order of hydrated radii is Cs+<Rb+<K+<Na+<Li+

$L i^{+} < N a^{+} < K^{+} < R b^{+} < C s^{+}$

$C s^{+} < R b^{+} < K^{+} < N a^{+} < L i^{+}$

$R b^{+} < N a^{+} < L i^{+} < C s^{+} < K^{+}$

$C s^{+} < K^{+} < R b^{+} < L i^{+} < N a^{+}$

$L i^{+}$ has highest hydration enthalpy.
Hence it is most hydrated
$∴$ Correct order of hydrated radii is
$C s^{+} < R b^{+} < K^{+} < N a^{+} < L i^{+}$