Which of the following holds if there was only one type of charge in the universe?

Question

Which of the following holds if there was only one type of charge in the universe? (A)  oints overset arrow E⋅ d overset arrow s≠ 0 on any surface. (B)  oints overset arrow E⋅ d overset arrow s=0 if the charge is outside the surface. (C)  oints overset arrow E⋅ d overset arrow s=(q/ϵ 0) if charge of magnitude q were inside the surface. (D) Both (.B.) and (.C.) are correct.

Tardigrade Admin · Accepted Answer

According to Gauss&rsquo;s theorem in electrostatics ointe overset arrow E ⋅ overset arrow d s = (q/ϵ 0) Here q is charge enclosed by the surface.If the charge is outside the surface, therefore qs n s i d e=0 Also, ointe overset arrow E ⋅ overset arrow d s = 0 .So both (b) and (c) are correct.

Q. Which of the following holds if there was only one type of charge in the universe?

$\oint_{s} E \to \cdot d s \to \neq = 0$ on any surface.

$\oint_{s} E \to \cdot d s \to = 0$ if the charge is outside the surface.

$\oint_{s} E \to \cdot d s \to = \frac{q}{ϵ _{0}}$ if charge of magnitude $q$ were inside the surface.

Both $(B)$ and $(C)$ are correct.

According to Gauss’s theorem in electrostatics $\oint_{e} E \to \cdot d \to s = \frac{q}{ϵ _{0}}$
Here $q$ is charge enclosed by the surface.If the charge is outside the surface, therefore $q_{s n s i d e} = 0$ Also,
$\oint_{e} E \to \cdot d \to s = 0$ .So both (b) and (c) are correct.

Q. Which of the following holds if there was only one type of charge in the universe?

∮s​E→⋅ds→=0 on any surface.

∮s​E→⋅ds→=0 if the charge is outside the surface.

∮s​E→⋅ds→=ϵ0​q​ if charge of magnitude q were inside the surface.

Both (B) and (C) are correct.

According to Gauss’s theorem in electrostatics ∮e​E→⋅d→s=ϵ0​q​ Here q is charge enclosed by the surface.If the charge is outside the surface, therefore qsnside​=0 Also, ∮e​E→⋅d→s=0 .So both (b) and (c) are correct.

$\oint_{s} E \to \cdot d s \to \neq = 0$ on any surface.

$\oint_{s} E \to \cdot d s \to = 0$ if the charge is outside the surface.

$\oint_{s} E \to \cdot d s \to = \frac{q}{ϵ _{0}}$ if charge of magnitude $q$ were inside the surface.

Both $(B)$ and $(C)$ are correct.

According to Gauss’s theorem in electrostatics $\oint_{e} E \to \cdot d \to s = \frac{q}{ϵ _{0}}$
Here $q$ is charge enclosed by the surface.If the charge is outside the surface, therefore $q_{s n s i d e} = 0$ Also,
$\oint_{e} E \to \cdot d \to s = 0$ .So both (b) and (c) are correct.