Question

Which of the following gives same number of ions as $A{l}_2(S{O}_4{)}_3$?

• A. $N{a}_{2}S{O}_4$
• B. $K_4[Fe(CN{)}_6]$
• C. $Al(N{O}_3{)}_3$
• D. $NaCl$

Answer 1

Answer: (B)

The no. of ions present in solution is equal to the van't Hoff factor
$A{l}_2{\left(S{O}_4\right)}_3:2A{l}^{3+}+3\left(S{O}_4^{2-}\right)\to 5$ ions
$K_4\left[Fe{\left(CN\right)}_6\right]:4K^{+}+{\left[Fe{\left(CN\right)}_6\right]}^{4-}\to 5$ ions