Question

Which of the following explanation is correct about the given below reaction?
$C{r}_2{O}_7^{2-}+H_{2}O\to 2Cr{O}_4^{2-}+2H^{+}$

• A. $Cr$ is reduced
• B. $Cr$ is oxidised
• C. Oxidation number of $Cr$ has neither decreased nor increased
• D. Hydrogen is reduced

Answer 1

Answer: (C)

The oxidation number of $Cr$ in $C{r}_2{O}_7^{2-}$ and $Cr{O}_4^2-$ is same, i.e. 6. Thus, oxidation of $Cr$ has neither decreased nor increased.