Which of the following does not represent the mathematical expression for the Heisenberg uncertainty principle?

Question

Which of the following does not represent the mathematical expression for the Heisenberg uncertainty principle? (A) Δ x . Δ P ge (h/(4π)) (B) Δ x . Δ v ge (h/(4π m)) (C) Δ E . Δ t ge (h/(4π)) (D) Δ E . Δ x ge (h/(4π))

Tardigrade Admin · Accepted Answer

From Heisenberg uncertainty principle, Δ x ⋅ Δ p ≥ (h/4 π) ...(i) or Δ x ⋅ m Δ v ≥ (h/4 π) or Δ x ⋅ Δ v ≥ (h/4 π m) ...(ii) This principle is also applicable for pairs like energy-time (Δ E ⋅ Δ t) and angular moment-angle (Δ w ⋅ Δ θ) along with position-moment (Δ x ⋅ Δ p). Thus, Δ E ⋅ Δ t ≥ (h/4 π) ...(iii)

Q. Which of the following does not represent the mathematical expression for the Heisenberg uncertainty principle?

$Δ x .Δ P \geq \frac{h}{( 4 π )}$

$Δ x .Δ v \geq \frac{h}{( 4 πm )}$

$Δ E .Δ t \geq \frac{h}{( 4 π )}$

$Δ E .Δ x \geq \frac{h}{( 4 π )}$

Q. Which of the following does not represent the mathematical expression for the Heisenberg uncertainty principle?

Δx.ΔP≥(4π)h​

Δx.Δv≥(4πm)h​

ΔE.Δt≥(4π)h​

ΔE.Δx≥(4π)h​

$Δ x .Δ P \geq \frac{h}{( 4 π )}$

$Δ x .Δ v \geq \frac{h}{( 4 πm )}$

$Δ E .Δ t \geq \frac{h}{( 4 π )}$

$Δ E .Δ x \geq \frac{h}{( 4 π )}$