Which of the following complexes does not show geometrical isomerism?

Question

Which of the following complexes does not show geometrical isomerism? (A)  [Pt(NH3)2Cl2  (B)  [CO(NH3)4Cl2]  (C)  [COCl2(en)2]  (D)  [Ni(CO)4]

Tardigrade Admin · Accepted Answer

Geometrical isomerism is not possible for the complexes with coordination number 2 and 3 and tetrahedral complexes with coordination number 4 because in this case, all the four positions are equivalent. Thus, amongst them, [Ni(CO4)] will not show geometrical isomerism.

Q. Which of the following complexes does not show geometrical isomerism?

$[Pt (N H_{3})_{2} C l_{2}$

$[CO (N H_{3})_{4} C l_{2}]$

$[COC l_{2} (e n)_{2}]$

$[N i (CO)_{4}]$

Geometrical isomerism is not possible for the complexes with coordination number $2$ and $3$ and tetrahedral complexes with coordination number $4$ because in this case, all the four positions are equivalent. Thus, amongst them, $[N i (C O_{4})]$ will not show geometrical isomerism.

Q. Which of the following complexes does not show geometrical isomerism?

[Pt(NH3​)2​Cl2​

[CO(NH3​)4​Cl2​]

[COCl2​(en)2​]

[Ni(CO)4​]

Geometrical isomerism is not possible for the complexes with coordination number 2 and 3 and tetrahedral complexes with coordination number 4 because in this case, all the four positions are equivalent. Thus, amongst them, [Ni(CO4​)] will not show geometrical isomerism.

$[Pt (N H_{3})_{2} C l_{2}$

$[CO (N H_{3})_{4} C l_{2}]$

$[COC l_{2} (e n)_{2}]$

$[N i (CO)_{4}]$

Geometrical isomerism is not possible for the complexes with coordination number $2$ and $3$ and tetrahedral complexes with coordination number $4$ because in this case, all the four positions are equivalent. Thus, amongst them, $[N i (C O_{4})]$ will not show geometrical isomerism.