Question

Which of the following circuits correctly represents the following truth table ?

A	B	C
0	0	0
0	1	0
1	0	1
1	1	0

• A.
• B.
• C.
• D.

Answer 1

Answer: (A)

For circuit 1
$A.B=\overline{Y+A}=C$
$AB\overline{y+A}=C$
$\begin{array}{ccccc}0& 0& 0& 1& 0\\ 0& 1& 0& 1& 0\\ 1& 0& 0& 0& 1\\ 1& 1& 1& 0& 0\end{array}$