Which hydride among the following is strongest reducing agent?

Question

Which hydride among the following is strongest reducing agent? (A) AsH3 (B) BiH3 (C) PH3 (D) SbH3

Tardigrade Admin · Accepted Answer

Among the given hydrides of group 15 elements,

B i H_{3}

is the strongest reducing agent. This is because as we move down the group, bond dissociation enthalpy decreases and thus reducing character increases. Hence, the order is

N H_{3} < P H_{3} < A s H_{3} < S b H_{3} < B i H_{3}

Q. Which hydride among the following is strongest reducing agent?

$A s H_{3}$

$B i H_{3}$

$P H_{3}$

$S b H_{3}$

Among the given hydrides of group 15 elements, $B i H_{3}$ is the strongest reducing agent. This is because as we move down the group, bond dissociation enthalpy decreases and thus reducing character increases. Hence, the order is

$N H_{3} < P H_{3} < A s H_{3} < S b H_{3} < B i H_{3}$

Q. Which hydride among the following is strongest reducing agent?

AsH3​

BiH3​

PH3​

SbH3​

Among the given hydrides of group 15 elements, BiH3​ is the strongest reducing agent. This is because as we move down the group, bond dissociation enthalpy decreases and thus reducing character increases. Hence, the order is NH3​<PH3​<AsH3​<SbH3​<BiH3​

$A s H_{3}$

$B i H_{3}$

$P H_{3}$

$S b H_{3}$

Among the given hydrides of group 15 elements, $B i H_{3}$ is the strongest reducing agent. This is because as we move down the group, bond dissociation enthalpy decreases and thus reducing character increases. Hence, the order is

$N H_{3} < P H_{3} < A s H_{3} < S b H_{3} < B i H_{3}$