Which has maximum number of millimoles of Cl - ion?

Question

Which has maximum number of millimoles of Cl - ion? (A) 0.208 g BaCl 2 (B) 100 mL of 0.1 M BaCl 2 (C) 0.745 g KCl (D) Equal

Tardigrade Admin · Accepted Answer

(a) 0.208 g BaCl 2=(0.208/208) mole =1 × 10-3 mole =1 millimole BaCl2 =2 millimoles Cl- (b) 0.1 millimoles BaCl =100 × 0.2 millimoles Cl - =20 millimoles (c) 0.745 g KCl =(0.745/74.5) mole KCl 2 =0.01 mole =0.01 × 1000 millimoles =10 millimoles

Q. Which has maximum number of millimoles of $C l^{-}$ ion?

$0.208 g B a C l_{2}$

$100 m L$ of $0.1 M B a C l_{2}$

$0.745 g K Cl$

Equal

Q. Which has maximum number of millimoles of Cl− ion?

0.208gBaCl2​

100mL of 0.1MBaCl2​

0.745gKCl

Equal

(a) 0.208gBaCl2​=2080.208​ mole =1×10−3 mole =1 millimole BaCl2​ =2 millimoles Cl− (b) 0.1 millimoles BaCl =100×0.2 millimoles Cl− =20 millimoles (c) 0.745gKCl=74.50.745​moleKCl2​ =0.01 mole =0.01×1000 millimoles =10 millimoles

Q. Which has maximum number of millimoles of $C l^{-}$ ion?

$0.208 g B a C l_{2}$

$100 m L$ of $0.1 M B a C l_{2}$

$0.745 g K Cl$