Question

Which give (s) yellow precipitate with $K_{2}Cr{O}_4$ ?

• A. $B{a}^{2+}$
• B. $C{d}^{2+}$
• C. $C{a}^{2+}$
• D. $S{r}^{2+}$

Answer 1

Answer: (A)

Among the given ions, only $B{a}^{2+}$ gives yellow precipitate of barium chromate, when treated with $K_{2}Cr{O}_4$ . $B{a}^{2+}+K_{2}Cr{O}_4\to \underset{yellowppt.}{BaCr{O}_4}+2K^{+}$