Q.
When two resistances R1 and R2 are connected in series, they consume 12W power. When they are connected in parallel, they consume 50W power. What the ratio of the powers of R1 and R2 ?
In series, ps=P1+P2P1×P2=12W
In parallel, Pp=P1+P2=50W ∴P1P2=12×50=600
Now, (p1−p2)2=(p1+p2)2−4p1p2 =(50)2−4×600 =2500−2400=100 ∴P1−P2=10
or P1=30W,P2=20W ∴P2P1=23