When the same quantity of current is passed through CuSO4 and AgNO3 solution 2.7 g of silver is deposited. The amount of copper deposited is

Question

When the same quantity of current is passed through CuSO4 and AgNO3 solution 2.7 g of silver is deposited. The amount of copper deposited is (A) 0.4 g (B) 3.2 g (C) 1.6 g (D) 0.8 g

Tardigrade Admin · Accepted Answer

According to Faraday's second law: ( Wt. of Cu deposited/ Wt. of Ag deposited) = (Eq. wt.of Cu/Eq. wt. of Ag) Wt. of Cu deposited = (Eq. wt. of Cu × Wt. of Ag deposited/ Eq. wt. of Ag) = (63.5 / 2 × 2.7/108) = 0.793 = 0.80 g

Q. When the same quantity of current is passed through CuSO4​ and AgNO3​ solution 2.7g of silver is deposited. The amount of copper deposited is

0.4 g

3.2 g

1.6 g

0.8 g

According to Faraday's second law : Wt.ofAgdepositedWt.ofCudeposited​=Eq.wt.ofAgEq.wt.ofCu​ Wt. of Cu deposited =Eq.wt.ofAgEq.wt.ofCu×Wt.ofAgdeposited​ =10863.5/2×2.7​=0.793=0.80g

Q. When the same quantity of current is passed through $C u S O_{4}$ and $A g N O_{3}$ solution $2.7 g$ of silver is deposited. The amount of copper deposited is